x-1-3-x-12-

Question Number 85358 by jagoll last updated on 21/Mar/20

\sqrt[3]{x} + \sqrt{x} = 12

Answered by john santu last updated on 21/Mar/20

x = t^{6}

\Rightarrow t^{2} + t^{3} - 12 = 0

(t - 2) (t^{2} + 3 t + 6) = 0

\Rightarrow t = 2 \Rightarrow x = 2^{6} = 64

\Rightarrow t = \frac{- 3 \pm i \sqrt{15}}{2}

\Rightarrow x = {(\frac{- 3 \pm i \sqrt{15}}{2})}^{6}

Commented by john santu last updated on 21/Mar/20

h a h a h a \dots u p s i d e d o w n s i r

Commented by MJS last updated on 21/Mar/20

sorry, but you made a weird mistake

x = t^{6}

\Rightarrow t^{3} + t^{2} - 12 = 0 \Rightarrow t = 2 \Rightarrow x = 2^{6} = 64

Commented by MJS last updated on 21/Mar/20

yes, I also tend to this kind of error sometimes

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