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x-1-log-3-9-3-x-3-1-




Question Number 159639 by bobhans last updated on 19/Nov/21
          ((x−1)/(log _3 (9−3^x )−3)) ≤ 1
x1log3(93x)31
Answered by tounghoungko last updated on 19/Nov/21
   ((x−1)/(log _3 (9−3^x )−log _3 (27))) ≤ 1 ; 9−3^x >0 ; x<2   ((x−1)/(log _3 (((9−3^x )/(27))))) ≤ 1     (x−1)log _((((9−3^x )/(27)))) (3) ≤ 1    log _((((9−3^x )/(27)))) (3^(x−1) ) ≤ 1    as x<2 , 0 < ((9−3^x )/(27)) < 1   3^(x−1 ) ≥ ((9−3^x )/(27))    9.3^x  ≥ 9−3^x  ; 10.3^x  ≥ 9   x ≥ log _3 ((9/(10)))    then x∈ [ log _3 ((9/(10))) , 2 )
x1log3(93x)log3(27)1;93x>0;x<2x1log3(93x27)1(x1)log(93x27)(3)1log(93x27)(3x1)1asx<2,0<93x27<13x193x279.3x93x;10.3x9xlog3(910)thenx[log3(910),2)

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