Question Number 180935 by SANOGO last updated on 19/Nov/22
$$\int_{} \frac{{x}+\mathrm{1}}{{x}^{\mathrm{2}} +\mathrm{1}}{dx} \\ $$
Answered by Frix last updated on 19/Nov/22
$$\int\frac{{x}+\mathrm{1}}{{x}^{\mathrm{2}} +\mathrm{1}}{dx}=\frac{\mathrm{1}}{\mathrm{2}}\int\frac{\mathrm{2}{x}}{{x}^{\mathrm{2}} +\mathrm{1}}{dx}+\int\frac{{dx}}{{x}^{\mathrm{2}} +\mathrm{1}}= \\ $$$$=\frac{\mathrm{ln}\:\left({x}^{\mathrm{2}} +\mathrm{1}\right)}{\mathrm{2}}+\mathrm{tan}^{−\mathrm{1}} \:{x}\:+{C} \\ $$
Commented by SANOGO last updated on 19/Nov/22
$${merci}\:{bien} \\ $$
Answered by Socracious last updated on 19/Nov/22
$$ \\ $$