Question Number 21813 by lakshmi.narasimhan last updated on 04/Oct/17
$${x}_{\mathrm{1}} +{x}_{\mathrm{2}} +{x}_{\mathrm{3}} =\mathrm{5} \\ $$$${ways}=\mathrm{5}−\mathrm{1}{C}_{\mathrm{3}−\mathrm{1}} =\mathrm{4}{C}_{\mathrm{2}} =\mathrm{6} \\ $$
x-1-x-2-x-3-5-ways-5-1C-3-1-4C-2-6-