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x-1-x-5-dx-




Question Number 113760 by gloriousman last updated on 15/Sep/20
∫(√((x−1)/x^5 ))dx
x1x5dx
Answered by bemath last updated on 15/Sep/20
I=∫ (1/x^2 )(√((x−1)/x)) dx   I= ∫ (1/x^2 ) (√(1−(1/x))) dx   [ let u = 1−(1/x) ⇒du = (dx/x^2 ) ]  I= ∫ u^(1/2)  du = (2/3)u^(3/2) + c  I= (2/3) (((x−1)/x))(√((x−1)/x)) + c
I=1x2x1xdxI=1x211xdx[letu=11xdu=dxx2]I=u12du=23u32+cI=23(x1x)x1x+c
Commented by gloriousman last updated on 15/Sep/20
Thanks
Thanks

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