x-1-x-5-dx- Tinku Tara June 4, 2023 Integration 0 Comments FacebookTweetPin Question Number 113760 by gloriousman last updated on 15/Sep/20 ∫x−1x5dx Answered by bemath last updated on 15/Sep/20 I=∫1x2x−1xdxI=∫1x21−1xdx[letu=1−1x⇒du=dxx2]I=∫u12du=23u32+cI=23(x−1x)x−1x+c Commented by gloriousman last updated on 15/Sep/20 Thanks Terms of Service Privacy Policy Contact: info@tinkutara.com FacebookTweetPin Post navigation Previous Previous post: prove-that-exp-2-pii-4-e-2-1-i-cos-z-1-z-2-cos-z-1-cos-z-2-sin-z-1-sin-z-2-Next Next post: Question-113763 Leave a Reply Cancel replyYour email address will not be published. Required fields are marked *Comment * Name * Save my name, email, and website in this browser for the next time I comment.