Question Number 32402 by saru53424@gmail.com last updated on 24/Mar/18
$$\int\frac{{x}+\mathrm{2}}{\mathrm{1}−{x}} \\ $$
Commented by abdo imad last updated on 24/Mar/18
$$\int\frac{{x}+\mathrm{2}}{\mathrm{1}−{x}}{dx}\:=−\int\:\frac{{x}+\mathrm{2}}{{x}−\mathrm{1}}{dx}\:=−\:\int\frac{{x}−\mathrm{1}+\mathrm{3}}{{x}−\mathrm{1}}{dx} \\ $$$$=−{x}\:−\mathrm{3}\int\:\frac{{dx}}{{x}−\mathrm{1}}\:=−{x}\:−\mathrm{3}{ln}\mid{x}−\mathrm{1}\mid\:+\lambda\:. \\ $$