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x-2-1-x-2-51-find-x-




Question Number 83672 by jagoll last updated on 05/Mar/20
x^2  + (1/x^2 ) = 51   find x
x2+1x2=51findx
Answered by john santu last updated on 05/Mar/20
x^2  + (1/x^2 ) = 51 ⇔ (x+(1/x))^2 −2 = x^2 +(1/x^2 )  (x+(1/x))^2 = 53 ⇒x+(1/x)= ± (√(53))  case (1) ⇒x+(1/x) = (√(53))  x^2 −x(√(53)) +1 = 0  x = (((√(53)) ± 7)/2) =  { ((x= (((√(53)) +7)/2))),((x = (((√(53)) −7)/2))) :}  case (2) ⇒x +(1/x) = −(√(53))  x^2  +x(√(53)) +1 =0  x = ((−(√(53)) ± 7)/2) =  { ((x= ((7−(√(53)))/2))),((x = ((−7−(√(53)))/2))) :}
x2+1x2=51(x+1x)22=x2+1x2(x+1x)2=53x+1x=±53case(1)x+1x=53x2x53+1=0x=53±72={x=53+72x=5372case(2)x+1x=53x2+x53+1=0x=53±72={x=7532x=7532
Answered by mr W last updated on 05/Mar/20
(x + (1/x))^2  = 53 ⇒x+(1/x)=±(√(53))  (x − (1/x))^2  = 49 ⇒x−(1/x)=±7  ⇒x=(1/2)(±(√(53))±7)= { ((((√(53))+7)/2)),((((√(53))−7)/2)),(((−(√(53))+7)/2)),(((−(√(53))−7)/2)) :}
(x+1x)2=53x+1x=±53(x1x)2=49x1x=±7x=12(±53±7)={53+72537253+725372

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