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Question Number 183935 by SulaymonNorboyev last updated on 31/Dec/22
(√(x^2 +2))+(√(x^2 −4))=A (√(x^2 +2))−(√(x^2 −4))=?
x2+2+x2−4=Ax2+2−x2−4=?
Answered by Rasheed.Sindhi last updated on 31/Dec/22
(√(x^2 +2))+(√(x^2 −4))=A (√(x^2 +2))−(√(x^2 −4))=? ((√(x^2 +2))+(√(x^2 −4)) )((√(x^2 +2)) −(√(x^2 −4)) ) =A((√(x^2 +2)) −(√(x^2 −4)) ) ((√(x^2 +2)) −(√(x^2 −4)) )=(1/A){(x^2 +2)−(x^2 −4)} (√(x^2 +2)) −(√(x^2 −4)) =(6/A)
x2+2+x2−4=Ax2+2−x2−4=?(x2+2+x2−4)(x2+2−x2−4)=A(x2+2−x2−4)(x2+2−x2−4)=1A{(x2+2)−(x2−4)}x2+2−x2−4=6A
Commented by SulaymonNorboyev last updated on 31/Dec/22
THANKS YOU
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Answered by Rasheed.Sindhi last updated on 31/Dec/22
(√(x^2 +2))+(√(x^2 −4))=A (√(x^2 +2))−(√(x^2 −4))=? a=(√(x^2 +2)) , b=(√(x^2 −4)) a+b=A.........(i) a^2 −b^2 =(x^2 +2)−(x^2 −4)=6 a−b=((a^2 −b^2 )/(a+b))=(6/A) (√(x^2 +2)) −(√(x^2 −4))=(6/A)
x2+2+x2−4=Ax2+2−x2−4=?a=x2+2,b=x2−4a+b=A………(i)a2−b2=(x2+2)−(x2−4)=6a−b=a2−b2a+b=6Ax2+2−x2−4=6A
Answered by manolex last updated on 31/Dec/22
m+n=A find m−n (m+n)(m−n)=(m−n)A x^2 +2−x^2 +4=(m−n)A (6/A)=(√(x^2 +2))− (√(x^2 −4)) is answer
m+n=Afindm−n(m+n)(m−n)=(m−n)Ax2+2−x2+4=(m−n)A6A=x2+2−x2−4isanswer

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