Menu Close

x-2-2-y-2-2-97-1-x-2-3-y-2-3-793-2-solve-the-simultaneous-equation-




Question Number 44783 by Necxx last updated on 04/Oct/18
(x^2 )^2 +(y^2 )^2 =97.......1  (x^2 )^3 +(y^2 )^3 =793.......2  solve the simultaneous equation
(x2)2+(y2)2=97.1(x2)3+(y2)3=793.2solvethesimultaneousequation
Answered by ajfour last updated on 05/Oct/18
a^2 +b^2  = 97  a^3 +b^3 = 793    ⇒  (a+b)^2 −2ab = 97    &    (a+b)^3 −3ab(a+b)=793  let  a+b = r    &  ab = s  ⇒   r^2 −2s = 97   &          r^3 −3rs = 793  ⇒   2r^3 −3r(r^3 −97)=1586  ⇒   r^3 −291r +1586 = 0  solution of a cubic of the form      x^3 +px+q = 0   is   x= (−(q/2)+(√((q^2 /4)+(p^3 /(27)))) )^(1/3)                   −((q/2)+(√((q^2 /4)+(p^3 /(27)))) )^(1/3)   (if it has one real root)  Here we have         r^3 −291r+1586 = 0    calculator provides the real root,     r = 13 , s = ((r^2 −97)/2) = ((169−97)/2)  ⇒  s = 36  ⇒  a+b = 13,  ab = 36  x= ±9,  y = ±4  or  x= ±4,  y= ±9 .
a2+b2=97a3+b3=793(a+b)22ab=97&(a+b)33ab(a+b)=793leta+b=r&ab=sr22s=97&r33rs=7932r33r(r397)=1586r3291r+1586=0solutionofacubicoftheformx3+px+q=0isx=(q2+q24+p327)1/3(q2+q24+p327)1/3(ifithasonerealroot)Herewehaver3291r+1586=0calculatorprovidestherealroot,r=13,s=r2972=169972s=36a+b=13,ab=36x=±9,y=±4orx=±4,y=±9.
Commented by Necxx last updated on 05/Oct/18
please solve how r=13.Thanks
pleasesolvehowr=13.Thanks
Commented by Necxx last updated on 05/Oct/18
Oh.... I really didnt remember  the cubic forms you and Mr MJS  used.Thanks so much
Oh.IreallydidntrememberthecubicformsyouandMrMJSused.Thankssomuch

Leave a Reply

Your email address will not be published. Required fields are marked *