Question Number 84826 by jagoll last updated on 16/Mar/20
$$\sqrt{\mathrm{x}^{\mathrm{2}} −\mathrm{2x}+\mathrm{2}}\:+\:\mathrm{log}_{\mathrm{3}} \:\sqrt{\mathrm{x}^{\mathrm{2}} −\mathrm{2x}+\mathrm{10}}\:=\:\mathrm{2} \\ $$
Commented by john santu last updated on 16/Mar/20
$$\mathrm{x}\:=\:\mathrm{1} \\ $$