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x-2-2x-2-log-3-x-2-2x-10-2-




Question Number 84826 by jagoll last updated on 16/Mar/20
(√(x^2 −2x+2)) + log_3  (√(x^2 −2x+10)) = 2
$$\sqrt{\mathrm{x}^{\mathrm{2}} −\mathrm{2x}+\mathrm{2}}\:+\:\mathrm{log}_{\mathrm{3}} \:\sqrt{\mathrm{x}^{\mathrm{2}} −\mathrm{2x}+\mathrm{10}}\:=\:\mathrm{2} \\ $$
Commented by john santu last updated on 16/Mar/20
x = 1
$$\mathrm{x}\:=\:\mathrm{1} \\ $$

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