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x-2-dy-dx-x-2-xy-y-2-




Question Number 94239 by i jagooll last updated on 17/May/20
x^2  (dy/dx) = x^2 +xy+y^2
$$\mathrm{x}^{\mathrm{2}} \:\frac{\mathrm{dy}}{\mathrm{dx}}\:=\:\mathrm{x}^{\mathrm{2}} +\mathrm{xy}+\mathrm{y}^{\mathrm{2}} \\ $$
Answered by i jagooll last updated on 17/May/20
Commented by john santu last updated on 18/May/20
the last step it should be   y = x tan (ln ∣Cx∣)
$$\mathrm{the}\:\mathrm{last}\:\mathrm{step}\:\mathrm{it}\:\mathrm{should}\:\mathrm{be}\: \\ $$$${y}\:=\:{x}\:\mathrm{tan}\:\left(\mathrm{ln}\:\mid\mathrm{C}{x}\mid\right)\: \\ $$

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