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x-2-x-2-5-2-x-3-2-dx-




Question Number 88307 by M±th+et£s last updated on 09/Apr/20
∫(x^2 /(x^2 −(5/2)x−(3/2))) dx
x2x252x32dx
Answered by TANMAY PANACEA. last updated on 09/Apr/20
∫((2x^2 )/(2x^2 −5x−3))  ∫((2x^2 )/(2x^2 −6x+x−3))dx  2∫(x^2 /(2x(x−3)+1(x−3)))dx  ∫((2x^2 dx)/((x−3)(2x+1)))  ((2x^2 )/((x−3)(2x+1)))=1+(a/(x−3))+(b/(2x+1))  2x^2 =2x^2 −5x−3+2ax+a+bx−b  0=x(2a+b−5)+(a−b−3)  2a+b−5=0  a−b−3=0  3a=8→a=(8/3)  b=(8/3)−3=((−1)/3)  ∫dx+(8/3)∫(dx/(x−3))+((−1)/3)∫(dx/(2x+1))  ∫dx+(8/3)∫(dx/(x−3))+((−1)/6)∫(dx/(x+(1/2)))  x+(8/3)ln(x−3)+((−1)/6)ln(x+(1/2))+c
2x22x25x32x22x26x+x3dx2x22x(x3)+1(x3)dx2x2dx(x3)(2x+1)2x2(x3)(2x+1)=1+ax3+b2x+12x2=2x25x3+2ax+a+bxb0=x(2a+b5)+(ab3)2a+b5=0ab3=03a=8a=83b=833=13dx+83dxx3+13dx2x+1dx+83dxx3+16dxx+12x+83ln(x3)+16ln(x+12)+c
Commented by M±th+et£s last updated on 09/Apr/20
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