x-2-xy-4x-y-2-xy-4y-log-16-x-1-y-1-x-2-y-2- Tinku Tara June 4, 2023 Algebra 0 Comments FacebookTweetPin Question Number 149040 by mathdanisur last updated on 02/Aug/21 {x2+xy=4xy2+xy=4y⇒log16(x1+y1+x2+y2)=? Answered by bramlexs22 last updated on 02/Aug/21 (1)+(2)⇔x2+2xy+y2=4(x+y)⇒(x+y)2=4(x+y);(x+y)(x+y−4)=0case(1)⇒x=−y⇒x2−x2=4x⇒{x1=0y1=0case(2)x=4−y⇒x(x+y)=4x;4x=4x→x2=λ,y2=4−λthenlog16(x1+y1+x2+y2)=log16(0+λ+4−λ)=log16(4)=12 Commented by mathdanisur last updated on 02/Aug/21 ThankYouSer,Cool Terms of Service Privacy Policy Contact: info@tinkutara.com FacebookTweetPin Post navigation Previous Previous post: Question-149043Next Next post: find-minimum-value-of-x-y-x-3-2-y-1-2- Leave a Reply Cancel replyYour email address will not be published. Required fields are marked *Comment * Name * Save my name, email, and website in this browser for the next time I comment.