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Question Number 85774 by M±th+et£s last updated on 24/Mar/20

(x_{2 n}) = 2^{2 n} {(\frac{x}{2})}_{n} {(\frac{x + 1}{2})}_{n}

{(x)}_{m n} = m^{m n} \underset{k = 0}{\prod^{m = 1}} {(\frac{x + k}{m})}_{n}, m \in z

n o w i f m i s r e l a t i v e n u m b e r s u c h a s \frac{3}{2}, m \in Q

{(x)}_{\frac{3}{2} n} = ? ?

h e l p m e