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x-3-2-x-3-x-1-x-2-




Question Number 89226 by cindiaulia last updated on 16/Apr/20
∫(((x^3 +2)/x^3 ))(√(x−(1/x^2 )))
(x3+2x3)x1x2
Commented by jagoll last updated on 16/Apr/20
∫ (1+(2/x^3 )) (√(x−(1/x^2 ))) dx   u = x−(1/x^2 ) ⇒du = 1+(2/x^3 )  ∫ u^(1/2)  du = (2/3)u^(3/2)  +c  = (2/3)(x−(1/x^2 ))^(3/2) +c
(1+2x3)x1x2dxu=x1x2du=1+2x3u12du=23u32+c=23(x1x2)32+c

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