x-3-3367-2-n-x-n-

Question Number 147566 by mathdanisur last updated on 21/Jul/21

x^{3} + 3367 = 2^{n} \Rightarrow x; n = ?

Answered by Olaf_Thorendsen last updated on 21/Jul/21

x^{3} + 3367 = 2^{n}

Solution for x \in N .

x = \sqrt[3]{2^{n} - 3367}

n ⩽ 11 \Rightarrow 2^{n} - 3367 < 0

n = 12 :

x = \sqrt[3]{2^{12} - 3367}

x = \sqrt[3]{2^{n} - 3367}

x = \sqrt[3]{729} = \sqrt[3]{9^{3}} = 9

\Rightarrow x = 9, n = 12 is a solution

Commented by mathdanisur last updated on 22/Jul/21

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