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x-3-x-2-3-1-3-x-x-2-




Question Number 81223 by ubaydulla last updated on 10/Feb/20
x(3^x +2)=3(1−3^x )−x^2
$${x}\left(\mathrm{3}^{{x}} +\mathrm{2}\right)=\mathrm{3}\left(\mathrm{1}−\mathrm{3}^{{x}} \right)−{x}^{\mathrm{2}} \\ $$
Answered by MJS last updated on 10/Feb/20
3^x x+2x−3+3^x 3+x^2 =0  (x+3)(3^x +x−1)=0  x=−3  3^x +x−1=0 has no other zero than x=0
$$\mathrm{3}^{{x}} {x}+\mathrm{2}{x}−\mathrm{3}+\mathrm{3}^{{x}} \mathrm{3}+{x}^{\mathrm{2}} =\mathrm{0} \\ $$$$\left({x}+\mathrm{3}\right)\left(\mathrm{3}^{{x}} +{x}−\mathrm{1}\right)=\mathrm{0} \\ $$$${x}=−\mathrm{3} \\ $$$$\mathrm{3}^{{x}} +{x}−\mathrm{1}=\mathrm{0}\:\mathrm{has}\:\mathrm{no}\:\mathrm{other}\:\mathrm{zero}\:\mathrm{than}\:{x}=\mathrm{0} \\ $$

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