Question Number 155631 by aunzo last updated on 03/Oct/21
$$\left({x}+\mathrm{3}\left({x}−\mathrm{2}\right)={x}+\mathrm{10}\right. \\ $$
Commented by aunzo last updated on 03/Oct/21
$${plss} \\ $$
Commented by Ar Brandon last updated on 03/Oct/21
$$\mathrm{syntax}\:\mathrm{error}\:! \\ $$
Answered by Rasheed.Sindhi last updated on 03/Oct/21
$${If}\:{it}'{s}\:{as}\:\left({x}+\mathrm{3}\right)\left({x}−\mathrm{2}\right)={x}+\mathrm{10} \\ $$$$\:\:\:\:\:\:\:\:\:\:{x}^{\mathrm{2}} +{x}−\mathrm{6}={x}+\mathrm{10} \\ $$$$\:\:\:\:\:\:\:\:\:\:{x}^{\mathrm{2}} −\mathrm{6}=\mathrm{10} \\ $$$$\:\:\:\:\:\:\:\:\:\:{x}^{\mathrm{2}} =\mathrm{10}+\mathrm{6}=\mathrm{16} \\ $$$$\:\:\:\:\:\:\:\:\:\:\:{x}=\pm\mathrm{4} \\ $$$${If}\:{it}'{s}\:{as}\:\left({x}+\mathrm{3}\left({x}−\mathrm{2}\right)\right)={x}+\mathrm{10} \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:{x}+\mathrm{3}{x}−\mathrm{6}={x}+\mathrm{10} \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\mathrm{4}{x}−{x}=\mathrm{10}+\mathrm{6}=\mathrm{16} \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\mathrm{3}{x}=\mathrm{16} \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:{x}=\frac{\mathrm{16}}{\mathrm{3}}=\mathrm{5}\frac{\mathrm{1}}{\mathrm{3}} \\ $$
Answered by peter frank last updated on 03/Oct/21
$$\mathrm{x}+\mathrm{3}\left(\mathrm{x}−\mathrm{2}\right)=\mathrm{x}+\mathrm{10} \\ $$$$\mathrm{x}+\mathrm{3x}−\mathrm{6}=\mathrm{x}+\mathrm{10} \\ $$$$\mathrm{4x}−\mathrm{6}=\mathrm{x}+\mathrm{10} \\ $$$$\mathrm{3x}=\mathrm{16} \\ $$$$\mathrm{x}=\frac{\mathrm{16}}{\mathrm{3}} \\ $$
Commented by ajfour last updated on 03/Oct/21
good notice!