Question Number 15707 by Joel577 last updated on 13/Jun/17
$${x}^{\mathrm{3}} \:+\:\left({y}\:+\:\mathrm{1}\right)^{\mathrm{2}} \:.\:\frac{{dy}}{{dx}}\:=\:\mathrm{0} \\ $$$$\mathrm{Find}\:{y} \\ $$
Answered by ajfour last updated on 13/Jun/17
$$\:\:\:\:\:\:\:\:\:{x}^{\mathrm{3}} {dx}+\left({y}+\mathrm{1}\right)^{\mathrm{2}} {dy}=\mathrm{0} \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\frac{{x}^{\mathrm{4}} }{\mathrm{4}}+\frac{\left({y}+\mathrm{1}\right)^{\mathrm{3}} }{\mathrm{3}}={c}\:. \\ $$
Commented by Joel577 last updated on 13/Jun/17
$${thank}\:{you}\:{very}\:{much} \\ $$