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x-3-y-3-z-3-3xyz-x-y-z-x-2-y-2-z-2-xy-yz-zx-if-x-y-z-0-then-x-3-y-3-z-3-3xyz-0-x-2-y-2-z-2-xy-yz-zx-0-




Question Number 188512 by vishal1234 last updated on 02/Mar/23
x^3 +y^3 +z^3 −3xyz=  (x+y+z) (x^2 +y^2 +z^2 −xy−yz−zx)  if x+y+z = 0, then  x^3 +y^3 +z^3 −3xyz  = 0×(x^2 +y^2 +z^2 −xy−yz−zx)  = 0
x3+y3+z33xyz=(x+y+z)(x2+y2+z2xyyzzx)ifx+y+z=0,thenx3+y3+z33xyz=0×(x2+y2+z2xyyzzx)=0

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