Question Number 36126 by Rasheed.Sindhi last updated on 29/May/18
$$\mathrm{x}^{\mathrm{4}} +\mathrm{10x}^{\mathrm{3}} +\mathrm{6x}−\mathrm{1} \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\overset{?} {=}\left({x}^{\mathrm{2}} +\frac{\sqrt{\mathrm{5}}−\mathrm{1}}{\mathrm{2}}\right)\left({x}^{\mathrm{2}} +\mathrm{10}{x}−\frac{\sqrt{\mathrm{5}}+\mathrm{1}}{\mathrm{2}}\right) \\ $$
Commented by Rasheed.Sindhi last updated on 29/May/18
$$\mathcal{E}{xactly}\:{sir},\:{this}\:{is}\:{not}\:{true}. \\ $$
Commented by Rasheed.Sindhi last updated on 29/May/18
$$\mathcal{D}{ear}\:\mathcal{A}{bu}\:\mathcal{B}{ehi} \\ $$$${In}\:{Q}#\mathrm{35844}\:\mathrm{you}\:\mathrm{factorize}\:{as}\:{above}. \\ $$$${Is}\:{this}\:{right}? \\ $$
Commented by MJS last updated on 29/May/18
$$\mathrm{but}\:\mathrm{this}\:\mathrm{is}\:\mathrm{not}\:\mathrm{true} \\ $$
Commented by behi83417@gmail.com last updated on 29/May/18
$${mr}\:{Rasheed}!\:{you}\:{are}\:{right}.{it}\:{is}\:{not} \\ $$$${true}.{it}\:{is}\:{just}\:{an}\:{idea}. \\ $$