Question Number 185536 by mathlove last updated on 23/Jan/23
$${x}^{\mathrm{4}} +{x}^{{ln}\mathrm{5}} =\mathrm{19} \\ $$$${x}^{{lnx}} +{ln}^{\mathrm{2}} {x}=\mathrm{4} \\ $$$${x}=? \\ $$
Commented by Frix last updated on 23/Jan/23
$$\mathrm{Approximate}\:\mathrm{with}\:\mathrm{a}\:\mathrm{calculator} \\ $$
Answered by MJS_new last updated on 23/Jan/23
$$\mathrm{the}\:\mathrm{solution}\:\mathrm{of}\:\mathrm{the}\:\mathrm{1}^{\mathrm{st}} \:\mathrm{equation}\:\mathrm{is}\:\mathrm{not}\:\mathrm{the} \\ $$$$\mathrm{same}\:\mathrm{as}\:\mathrm{the}\:\mathrm{solution}\:\mathrm{of}\:\mathrm{the}\:\mathrm{2}^{\mathrm{nd}} \:\mathrm{equation} \\ $$