x-6-64-4-2x-1-x-2-x-2-4-4x-1-x-2-4x-2-2x-1-1-2x-dx-

Question Number 124101 by Ar Brandon last updated on 30/Nov/20

\int (\frac{x^{- 6} - 64}{4 + {2 x}^{- 1} + x^{- 2}} \cdot \frac{x^{2}}{4 - {4 x}^{- 1} + x^{- 2}} - \frac{{4 x}^{2} (2 x + 1)}{1 - 2 x}) dx

Answered by MJS_new last updated on 30/Nov/20

= \int 2 x + 1 d x = x^{2} + x + C

Commented by Ar Brandon last updated on 30/Nov/20

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