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x-6-x-2-x-8-x-4-1-dx-




Question Number 86824 by Ar Brandon last updated on 31/Mar/20
∫((x^6 +x^2 )/(x^8 −x^4 +1))dx
x6+x2x8x4+1dx
Answered by TANMAY PANACEA. last updated on 31/Mar/20
∫((x^2 +(1/x^2 ))/(x^4 −1+(1/x^4 )))dx  ∫((x^2 +(1/x^2 ))/((x^2 +(1/x^2 ))^2 −3))dx  (1/2)∫((x^2 +(1/x^2 )+(√3) +x^2 +(1/x^2 )−(√3))/((x^2 +(1/x^2 )+(√3) )(x^2 +(1/x^2 )−(√3) )))dx  (1/2)∫(dx/(x^2 +(1/x^2 )−(√3)))+(1/2)∫(dx/(x^2 +(1/x^2 )+(√3)))  (1/4)∫((1−(1/x^2 )+1+(1/x^2 ))/(x^2 +(1/x^2 )−(√3)))dx+(1/4)∫((1−(1/x^2 )+1+(1/x^2 ))/(x^2 +(1/x^2 )+(√3)))dx  (1/4)∫((d(x+(1/x)))/((x+(1/x))^2 −(2+(√3) )))+(1/4)∫((d(x−(1/x)))/((x−(1/x))^2 +2−(√3) ))+(1/4)∫((d(x+(1/x)))/((x+(1/x))^2 −2+(√3)))+(1/4)∫((d(x−(1/x)))/((x−(1/x))^2 +2+(√3)))  (1/4)×(1/(2(√(2+(√3) ))))ln(((x+(1/x)−(√(2+(√3))))/(x+(1/x)+(√(2+(√3))))))=I_1   (1/4)×(1/( (√(2−(√3)))))tan^(−1) (((x−(1/x))/( (√(2−(√3))))))=I_2   (1/4)×(1/(2(√(2−(√3)))))ln(((x+(1/x)−(√(2−(√3))))/(x+(1/x)+(√(2−(√3))))))=I_3   (1/4)×(1/( (√(2+(√3)))))tan^(−1) (((x−(1/x))/( (√(2+(√3))))))  pls add them...
x2+1x2x41+1x4dxx2+1x2(x2+1x2)23dx12x2+1x2+3+x2+1x23(x2+1x2+3)(x2+1x23)dx12dxx2+1x23+12dxx2+1x2+31411x2+1+1x2x2+1x23dx+1411x2+1+1x2x2+1x2+3dx14d(x+1x)(x+1x)2(2+3)+14d(x1x)(x1x)2+23+14d(x+1x)(x+1x)22+3+14d(x1x)(x1x)2+2+314×122+3ln(x+1x2+3x+1x+2+3)=I114×123tan1(x1x23)=I214×1223ln(x+1x23x+1x+23)=I314×12+3tan1(x1x2+3)plsaddthem
Commented by Ar Brandon last updated on 02/Apr/20
Amazing  !
Amazing!
Commented by TANMAY PANACEA. last updated on 02/Apr/20
thank you sir...
thankyousir
Answered by M±th+et£s last updated on 03/Apr/20
(1/2)∫((2(x^6 +x^2 ))/(x^8 +2x^4 +1−3x^4 ))dx=(1/2)∫((x^6 +x^6 +(√3)x^4 −(√3)x^4 +x^2 +x^2 )/((x^4 +1)^2 −3x^4 ))dx  (1/2)∫((x^6 +(√3)x^4 +x^2  +x^6 −(√3)x^4 +x^2 )/((x^4 +1−(√3)x^2 )(x^4 +1+(√3)x^2 )))dx  (1/2)∫((x^2 (x^4 +(√3)x^2 +1)+x^2 (x^4 −(√3)x^2 +1))/((x^4 +1−(√3)x^2 )(x^4 +1+(√3)x^2 )))dx  (1/4)∫(((2x^2 )/((x^4 +1+(√3)x^2 ))) + ((2x^2 )/((x^4 +1−(√3)x^2 )))dx  (1/4)∫(((x^2 +1+x^2 −1)/((x^4 +1+(√3)x^2 )))+((x^2 +1+x^2 −1)/((x^4 +1−(√3)x^2 ))))dx  (1/4)∫(((x^2 +1)/(x^4 +1+(√3)x^2 )) +((x^2 −1)/(x^4 +1+(√3)x^2 ))+((x^2 +1)/(x^4 +1−(√3)x^2 ))+((x^2 −1)/(x^4 +1−(√3)x^2 )))dx  (1/4)∫(((1+1/x^2 )/(x^2 +(√3)+1/x^2 ))dx +((1−1/x^2 )/(x^2 +(√3)+1/x^2 ))+((1+1/x^2 )/(x^2 −(√3)+1/x^2 ))+((1−1/x^2 )/(x^2 −(√3)+1/x^2 )))dx  (1/4)∫(((1+1/x^2 )/(x^2 −2+1/x^2 −(√3)+2))+((1−1/x^2 )/(x^2 +2+1/x^2 −2−(√3)))+((1+1/x^2 )/(x^2 −2+1/x^2 +2+(√3)))+((1−1/x^2 )/(x^2 +2+1/x^2 −2+(√3))))  (1/4)∫(((1+1/x^2 )/((x−1/x)^2 −((√3)−2)))+((1−1/x^2 )/((x+1/x)^2 −(2+(√3))))+((1+1/x^2 )/((x−1/x)^2 +((√3)+2)))+((1−1/x^2 )/((x−1/x)^2 +((√3)−2))))dx  (1/(4(√(2−(√3)))))tanh^(−1) (1/( (√(2−(√3)))))(x−(1/x))+(1/(4(√(2−(√3)))))tanh^(−1) (1/( (√(2−(√3)))))(x+(1/x))+(1/(4(√((√3)+2))))tan^(−1) (1/( (√((√3)+2))))(x−(1/x))+(1/(4(√((√3)−2))))tan^(−1) (1/( (√((√3)−2))))(x+(1/x))+c        pls check
122(x6+x2)x8+2x4+13x4dx=12x6+x6+3x43x4+x2+x2(x4+1)23x4dx12x6+3x4+x2+x63x4+x2(x4+13x2)(x4+1+3x2)dx12x2(x4+3x2+1)+x2(x43x2+1)(x4+13x2)(x4+1+3x2)dx14(2x2(x4+1+3x2)+2x2(x4+13x2)dx14(x2+1+x21(x4+1+3x2)+x2+1+x21(x4+13x2))dx14(x2+1x4+1+3x2+x21x4+1+3x2+x2+1x4+13x2+x21x4+13x2)dx14(1+1/x2x2+3+1/x2dx+11/x2x2+3+1/x2+1+1/x2x23+1/x2+11/x2x23+1/x2)dx14(1+1/x2x22+1/x23+2+11/x2x2+2+1/x223+1+1/x2x22+1/x2+2+3+11/x2x2+2+1/x22+3)14(1+1/x2(x1/x)2(32)+11/x2(x+1/x)2(2+3)+1+1/x2(x1/x)2+(3+2)+11/x2(x1/x)2+(32))dx1423tanh1123(x1x)+1423tanh1123(x+1x)+143+2tan113+2(x1x)+1432tan1132(x+1x)+cplscheck

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