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x-99-y-99-x-100-Interger-solutions-




Question Number 175639 by Linton last updated on 04/Sep/22
x^(99) +y^(99) = x^(100)   Interger solutions?
x99+y99=x100Intergersolutions?
Answered by BaliramKumar last updated on 04/Sep/22
x^(99) [1 + ((y/x))^(99) ] = x^(100)    1 + ((y/x))^(99)  = x   ((y/x))^(99)  = x−1  (y/x) = ((x−1))^(1/(99))   y  = x(((x−1))^(1/(99)) )   (0, 0)       &    (1, 0)
x99[1+(yx)99]=x1001+(yx)99=x(yx)99=x1yx=x199y=x(x199)(0,0)&(1,0)

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