x-and-y-are-positive-integers-and-x-x-8y-4x-If-x-is-not-a-multiple-of-8-then-what-is-the-minimum-possible-value-for-y-

Question Number 160092 by abdullah_ff last updated on 24/Nov/21

x and y are positive integers and

x \times x - 8 y = 4 x .

If x is not a multiple of 8, then what is

the minimum possible value for y ?

Answered by FongXD last updated on 24/Nov/21

x^{2} - 8 y = 4 x

\Rightarrow y = \frac{x (x - 4)}{8} \in N

\Rightarrow x - 4 is a multiple of 8, \Rightarrow x = 8 t + 4, t \in N

minimum possible value for y = \frac{12 (12 - 4)}{8} = 12

Commented by abdullah_ff last updated on 24/Nov/21

t h a n k y o u v e r y m u c h s i r

Commented by Rasheed.Sindhi last updated on 24/Nov/21

C o m p a c t & E f f i c i e n t!