x-C-h-2-3-s-2-x-C-2-a-2-x-A-h-2-3-s-2-x-A-2-c-2-x-C-x-A-2-b-2-4-

Question Number 56264 by ajfour last updated on 13/Mar/19

{(x_{C} - h)}^{2} + 3 {(\frac{s}{2} - x_{C})}^{2} = a^{2}

{(x_{A} - h)}^{2} + 3 {(\frac{s}{2} + x_{A})}^{2} = c^{2}

{(x_{C} - x_{A})}^{2} = b^{2} / 4 .

Commented by MJS last updated on 12/Mar/19

seems impossible

Commented by ajfour last updated on 13/Mar/19

Commented by ajfour last updated on 13/Mar/19

F i n d m a x i m u m a n d m i n i m u m

v a l u e o f e d g e l e n g t h s o f

c i r c u m s c r i b i n g e q u i l a t e r a l △ .

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