Question Number 188098 by MathsFan last updated on 25/Feb/23
$$\int\boldsymbol{\mathrm{x}}!\boldsymbol{\mathrm{dx}} \\ $$
Answered by aba last updated on 25/Feb/23
$$\int{x}!{dx}=\int\Gamma\left({x}+\mathrm{1}\right){dx}=\int\int_{\mathrm{0}} ^{\infty} \mathrm{t}^{\mathrm{x}−\mathrm{1}} \mathrm{e}^{−{t}} {dtdx} \\ $$