x-dx-a-4-x-4- Tinku Tara June 4, 2023 Geometry 0 Comments FacebookTweetPin Question Number 25290 by rather ishfaq last updated on 07/Dec/17 ∫xdxa4+x4 Answered by prakash jain last updated on 07/Dec/17 x2=a2sinhu2xdx=a2coshudu∫a2coshudu2a2coshu=12u+C=12sinh−1x2a2+C Answered by ajfour last updated on 07/Dec/17 letx2=a2tanθ⇒2xdx=a2sec2θdθ∫xdxa4+x4=a22∫sec2θdθa2secθ=12ln∣secθ+tanθ∣+c1=12ln∣x2+a2+x2a2∣+c1=12ln(x2+x2+a2)+c. Terms of Service Privacy Policy Contact: info@tinkutara.com FacebookTweetPin Post navigation Previous Previous post: 0-pi-2-t-2n-sin-2n-tdt-Next Next post: solve-by-betta-function-0-2pi-sin-5-z-dz- Leave a Reply Cancel replyYour email address will not be published. Required fields are marked *Comment * Name * Save my name, email, and website in this browser for the next time I comment.