x-n-cos-nx-dx- Tinku Tara June 4, 2023 Integration 0 Comments FacebookTweetPin Question Number 152186 by Tawa11 last updated on 26/Aug/21 ∫xncos(nx)dx Answered by mindispower last updated on 26/Aug/21 nx=y⇔1nn+1∫yncos(x)dx=12.nn+1(∫yneiydy+∫yne−iydy)iy=−t,infirst−iy=−w2nd⇒=12.1nn+1(in+1∫tne−tdt+(−i)n+1∫wne−wdt)in+12.nn+1∫tne−tdt+(−i)n+1nn+1∫wne−wdwrecallΓ(a,x)incompletGammafunctionΓ(a,x):∫0atx−1e−tdtWeGetin+12.nn+1Γ(t,n+1)+(−i)n+12.nn+1Γ(w,n+1)=12(in)n+1Γ(−inx,n+1)+12(−in)n+1Γ(inx,n+1)∫xncos(nx)dx=12(in)n+1(Γ(−inx,n+1)+(−1)n+1Γ(inx,n+1))+c Commented by Tawa11 last updated on 26/Aug/21 Thankssir.Godblessyou. Commented by mindispower last updated on 28/Aug/21 pleasursir Terms of Service Privacy Policy Contact: info@tinkutara.com FacebookTweetPin Post navigation Previous Previous post: 0-1-ln-1-x-x-2-1-dx-Next Next post: Please-formular-for-8-3- Leave a Reply Cancel replyYour email address will not be published. Required fields are marked *Comment * Name * Save my name, email, and website in this browser for the next time I comment.