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x-n-cos-nx-dx-




Question Number 152186 by Tawa11 last updated on 26/Aug/21
∫x^n  cos(nx) dx
xncos(nx)dx
Answered by mindispower last updated on 26/Aug/21
nx=y  ⇔(1/n^(n+1) )∫y^n cos(x)dx  =(1/(2.n^(n+1) ))(∫y^n e^(iy) dy+∫y^n e^(−iy) dy)  iy=−t,in first −iy=−w  2nd⇒  =(1/2).(1/n^(n+1) )(i^(n+1) ∫t^n e^(−t) dt+(−i)^(n+1) ∫w^n e^(−w) dt)  (i^(n+1) /(2.n^(n+1) ))∫t^n e^(−t) dt+(((−i)^(n+1) )/n^(n+1) )∫w^n e^(−w) dw  recall Γ(a,x) incomplet Gamma function  Γ(a,x): ∫_0 ^a t^(x−1) e^(−t) dt  We Get   (i^(n+1) /(2.n^(n+1) ))Γ(t,n+1)+(((−i)^(n+1) )/(2.n^(n+1) ))Γ(w,n+1)  =(1/2)((i/n))^(n+1) Γ(−inx,n+1)+(1/2)(−(i/n))^(n+1) Γ(inx,n+1)  ∫x^n cos(nx)dx  =(1/2)((i/n))^(n+1) (Γ(−inx,n+1)+(−1)^(n+1) Γ(inx,n+1))+c
nx=y1nn+1yncos(x)dx=12.nn+1(yneiydy+yneiydy)iy=t,infirstiy=w2nd=12.1nn+1(in+1tnetdt+(i)n+1wnewdt)in+12.nn+1tnetdt+(i)n+1nn+1wnewdwrecallΓ(a,x)incompletGammafunctionΓ(a,x):0atx1etdtWeGetin+12.nn+1Γ(t,n+1)+(i)n+12.nn+1Γ(w,n+1)=12(in)n+1Γ(inx,n+1)+12(in)n+1Γ(inx,n+1)xncos(nx)dx=12(in)n+1(Γ(inx,n+1)+(1)n+1Γ(inx,n+1))+c
Commented by Tawa11 last updated on 26/Aug/21
Thanks sir. God bless you.
Thankssir.Godblessyou.
Commented by mindispower last updated on 28/Aug/21
pleasur sir
pleasursir

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