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x-sin-2-x-3-dx-




Question Number 98246 by  M±th+et+s last updated on 12/Jun/20
∫(x/(sin^2 (x−3)))dx
$$\int\frac{{x}}{{sin}^{\mathrm{2}} \left({x}−\mathrm{3}\right)}{dx} \\ $$
Answered by smridha last updated on 13/Jun/20
=∫xcosec^2 (x−3)dx  =−xcot(x−3)+∫((dsin(x−3))/(sin(x−3)))  =−xcot(x−3)+ln(sin(x−3))+c
$$=\int\boldsymbol{{xcosec}}^{\mathrm{2}} \left(\boldsymbol{{x}}−\mathrm{3}\right)\boldsymbol{{dx}} \\ $$$$=−\boldsymbol{{xcot}}\left(\boldsymbol{{x}}−\mathrm{3}\right)+\int\frac{{d}\boldsymbol{{sin}}\left(\boldsymbol{{x}}−\mathrm{3}\right)}{\boldsymbol{{sin}}\left(\boldsymbol{{x}}−\mathrm{3}\right)} \\ $$$$=−\boldsymbol{{xcot}}\left(\boldsymbol{{x}}−\mathrm{3}\right)+\boldsymbol{{ln}}\left(\boldsymbol{{sin}}\left(\boldsymbol{{x}}−\mathrm{3}\right)\right)+\boldsymbol{{c}} \\ $$
Commented by smridha last updated on 13/Jun/20
someone wanted to jok with me....is it seriously??but I think he has no basic idea of mathematics!!!
Commented by  M±th+et+s last updated on 13/Jun/20
correct and nice thanks
$${correct}\:{and}\:{nice}\:{thanks} \\ $$
Commented by smridha last updated on 13/Jun/20
I dont know who..did this  but when one challage someone  please comes with evidence..  your most welcome..
$$\boldsymbol{{I}}\:\boldsymbol{{dont}}\:\boldsymbol{{know}}\:\boldsymbol{{who}}..\boldsymbol{{did}}\:\boldsymbol{{this}} \\ $$$$\boldsymbol{{but}}\:\boldsymbol{{when}}\:\boldsymbol{{one}}\:\boldsymbol{{challage}}\:\boldsymbol{{someone}} \\ $$$$\boldsymbol{{please}}\:\boldsymbol{{comes}}\:\boldsymbol{{with}}\:\boldsymbol{{evidence}}.. \\ $$$$\boldsymbol{{your}}\:\boldsymbol{{most}}\:\boldsymbol{{welcome}}.. \\ $$

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