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x-t-2sin-pit-3-y-t-3cos-pit-3-4-cm-What-is-the-velocity-at-t-1s-




Question Number 183440 by aurpeyz last updated on 25/Dec/22
x(t)=2sin(((πt)/3))  y(t)=−3cos(((πt)/3))+4 cm  What is the velocity at t=1s
x(t)=2sin(πt3)y(t)=3cos(πt3)+4cmWhatisthevelocityatt=1s
Answered by cortano1 last updated on 26/Dec/22
 v = (dy/dx) , t=1     { (((dy/dt)=π sin (((πt)/3)))),(((dx/dt) = ((2π)/3) cos (((πt)/3)))) :}   (dy/dx) = (dy/dt) .(dt/dx) = π sin (((πt)/3)).(3/(2π cos (((πt)/3)) ))   = (3/2) tan (((πt)/3)) , t=1   ((dy/dx))_(t=1) = (3/2).tan ((π/3))=((3(√3))/2) cm/sec
v=dydx,t=1{dydt=πsin(πt3)dxdt=2π3cos(πt3)dydx=dydt.dtdx=πsin(πt3).32πcos(πt3)=32tan(πt3),t=1(dydx)t=1=32.tan(π3)=332cm/sec
Commented by mr W last updated on 26/Dec/22
but (dy/dx) is not the velocity, it′s the   direction of velocity.
butdydxisnotthevelocity,itsthedirectionofvelocity.
Answered by mr W last updated on 26/Dec/22
v_x =(dx/dt)=((2π)/3) cos ((πt)/3)=((2π)/3) cos (π/3)=(π/3)  v_y =(dy/dt)=π sin ((πt)/3)=π sin (π/3)=((π(√3))/2)  v=(√(v_x ^2 +v_y ^2 ))=(√(((π/3))^2 +(((π(√3))/2))^2 ))=((π(√(31)))/6) (m/s)
vx=dxdt=2π3cosπt3=2π3cosπ3=π3vy=dydt=πsinπt3=πsinπ3=π32v=vx2+vy2=(π3)2+(π32)2=π316ms
Commented by aurpeyz last updated on 26/Dec/22
So final answer will be 2.92? using π=3.142  initially at my first attempt i was confused  how that i will use π as 3.142 and then as  180 for sin and cos
Sofinalanswerwillbe2.92?usingπ=3.142initiallyatmyfirstattemptiwasconfusedhowthatiwilluseπas3.142andthenas180forsinandcos

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