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x-x-1-2-12-x-1-




Question Number 109699 by bemath last updated on 25/Aug/20
     x(x−1)^2  ≥ 12(x−1)
x(x1)212(x1)
Answered by bemath last updated on 25/Aug/20
⇔ (x−1)(x(x−1)−12)≥0  ⇔(x−1)(x−4)(x+3)≥0  ⇔ −3≤x≤1 ∪ x≥4
(x1)(x(x1)12)0(x1)(x4)(x+3)03x1x4
Commented by nimnim last updated on 25/Aug/20
Nice..
Nice..

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