x-x-1-2-2x-1-how-can-it-solve-this-help-me-please-

Question Number 150916 by tabata last updated on 16/Aug/21

x^{{(x - 1)}^{2}} = 2 x + 1

h o w c a n i t s o l v e t h i s ? h e l p m e p l e a s e

Answered by MJS_new last updated on 17/Aug/21

I {don}^{'} t think we can generally solve

x^{{(x - 1)}^{2}} = a x + b

but in this special case we can :

let t = x - 1 \Leftrightarrow x = t + 1

{(t + 1)}^{t^{2}} = 2 t + 3

let n = t^{2} \Leftrightarrow t = \pm \sqrt{n}

{(1 \pm \sqrt{n})}^{n} = 3 \pm 2 \sqrt{n}

obviously n = 2

\Rightarrow t = \pm \sqrt{2} \Rightarrow x = 1 \pm \sqrt{2}

Commented by tabata last updated on 16/Aug/21

t h a n k y o u s i r

Commented by tabata last updated on 16/Aug/21

a l s o 1 - \sqrt{2} i s s o l u t i o n o f t h i s e q u a t i o n

Commented by MJS_new last updated on 17/Aug/21

yes, thank you .

Commented by otchereabdullai@gmail.com last updated on 22/Aug/21

nice