Menu Close

x-x-1-x-x-2-x-1-find-x-

Tinku Tara 0 Comments
Pin




Question Number 144860 by mathdanisur last updated on 29/Jun/21
∣(x/(x-1))∣ + ∣x∣ = (x^2 /(∣x-1∣)) find x=?
∣xx−1∣+∣x∣=x2∣x−1∣findx=?
Commented by hknkrc46 last updated on 29/Jun/21
★ ∣x∣ = ((x^2 − ∣x∣)/(∣x − 1∣)) ★ ∣x^2 − x∣ = x^2 − ∣x∣ (a) x ∈ [0,1) ⇒ x − x^2 = x^2 − x ⇒ x = 0 (b) x ∈ R^− ⇒ x^2 − x = x^2 + x ⇒ x = 0 ∉ R^− (c) x ∈ (1 , ∞) ⇒ x^2 − x = x^2 − x ⇒ 0 = 0 ♣ x ∈ (1 , ∞) ∪ {0}
★∣x∣=x2−∣x∣∣x−1∣★∣x2−x∣=x2−∣x∣(a)x∈[0,1)⇒x−x2=x2−x⇒x=0(b)x∈R−⇒x2−x=x2+x⇒x=0∉R−(c)x∈(1,∞)⇒x2−x=x2−x⇒0=0♣x∈(1,∞)∪{0}
Commented by mathdanisur last updated on 30/Jun/21
alot cool Sir thanks
alotcoolSirthanks

Pin

Leave a Reply

Your email address will not be published. Required fields are marked *