x-x-2-1-y-y-2-1-2021-x-y-R-min-x-y-

Question Number 160603 by cortano last updated on 03/Dec/21

(x + \sqrt{x^{2} + 1}) (y + \sqrt{y^{2} + 1}) = 2021

\forall x, y \in R^{+} . \min (x + y) = ?

Answered by MJS_new last updated on 03/Dec/21

of all rectangles with sides a, b and given

area a \times b = A the square is the one with

the least perimeter \Leftrightarrow \min (a + b) is at

a = b = \sqrt{A}

\Rightarrow y = x

{(x + \sqrt{x^{2} + 1})}^{2} = 2021

{it}^{'} s easy to solve

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