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x-x-2-x-x-3-10x-4-find-x-




Question Number 163902 by HongKing last updated on 11/Jan/22
(√(x!^(x!) ))  +  2^(x!)   = x!^3   +  10x!  +  4  find:  x = ?
$$\sqrt{\mathrm{x}!^{\boldsymbol{\mathrm{x}}!} }\:\:+\:\:\mathrm{2}^{\boldsymbol{\mathrm{x}}!} \:\:=\:\mathrm{x}!^{\mathrm{3}} \:\:+\:\:\mathrm{10x}!\:\:+\:\:\mathrm{4} \\ $$$$\mathrm{find}:\:\:\boldsymbol{\mathrm{x}}\:=\:? \\ $$
Answered by MJS_new last updated on 11/Jan/22
x! is defined for x∈N ⇒ try the first few...  ⇒ x=3
$${x}!\:\mathrm{is}\:\mathrm{defined}\:\mathrm{for}\:{x}\in\mathbb{N}\:\Rightarrow\:\mathrm{try}\:\mathrm{the}\:\mathrm{first}\:\mathrm{few}… \\ $$$$\Rightarrow\:{x}=\mathrm{3} \\ $$

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