x-x-3-1-dx-Please-help- Tinku Tara June 4, 2023 Logarithms 0 Comments FacebookTweetPin Question Number 112773 by 675480065 last updated on 09/Sep/20 ∫xx3+1dxPleasehelp Answered by MJS_new last updated on 09/Sep/20 ∫xx3+1dx=[t=x3/2→dx=2dt3x]=23∫dtt2+1=23arctant==23arctanx3/2+C Terms of Service Privacy Policy Contact: info@tinkutara.com FacebookTweetPin Post navigation Previous Previous post: Question-178305Next Next post: Question-47243 Leave a Reply Cancel replyYour email address will not be published. Required fields are marked *Comment * Name * Save my name, email, and website in this browser for the next time I comment.