Question Number 18299 by tawa tawa last updated on 18/Jul/17
$$\mathrm{x}^{\mathrm{x}^{\mathrm{x}} } \:=\:\mathrm{2},\:\:\:\:\:\:\mathrm{find}\:\:\mathrm{x} \\ $$
Commented by mrW1 last updated on 19/Jul/17
$$\mathrm{no}\:\mathrm{analytic}\:\mathrm{solution} \\ $$$$\sqrt{\mathrm{2}}<\mathrm{x}<\mathrm{2} \\ $$
Commented by tawa tawa last updated on 19/Jul/17
$$\mathrm{God}\:\mathrm{bless}\:\mathrm{you}\:\mathrm{sir}. \\ $$