Menu Close

x-y-N-0-1-x-y-find-z-N-with-z-x-y-




Question Number 94786 by MJS last updated on 21/May/20
x, y ∈N\{0, 1} ∧ x≤y  find z∈N with z!=x!y!
x,yN{0,1}xyfindzNwithz!=x!y!
Commented by hknkrc46 last updated on 21/May/20
(a) x!=y+1 ⇒ z!=(y+1)! ⇒ z=y+1   (a.1) x=3⇒y=5⇒z=6  (a.2) x=4⇒y=23⇒z=24  (a.3) x=5⇒y=119⇒z=120  ∙∙∙∙  {x,y,z : x!=y+1=z ; x≥3}  (b) y!=x+1 ⇒ z!=(x+1)! ⇒ z=x+1  (b.1) y=3⇒x=5⇒z=6 (x≰y)  (b.2) y=4⇒x=23⇒z=24 (x≰y)  ....
(a)x!=y+1z!=(y+1)!z=y+1(a.1)x=3y=5z=6(a.2)x=4y=23z=24(a.3)x=5y=119z=120{x,y,z:x!=y+1=z;x3}(b)y!=x+1z!=(x+1)!z=x+1(b.1)y=3x=5z=6(xy)(b.2)y=4x=23z=24(xy).

Leave a Reply

Your email address will not be published. Required fields are marked *