x-y-z-gt-0-Solve-for-real-numbers-x-3-y-3-z-3-3-x-1-3-y-1-3-z-1-3-12-x-y-z-1-

Question Number 158363 by HongKing last updated on 03/Nov/21

x; y; z > 0

Solve for real numbers :

{\begin{cases} x^{3} + y^{3} + z^{3} + 3 \cdot (\sqrt[3]{x} + \sqrt[3]{y} + \sqrt[3]{z}) = 12 \\ x \cdot y \cdot z = 1 \end{cases}

Answered by GuruBelakangPadang last updated on 03/Nov/21

s i m e t r i c e : x = y = z = 1