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x-y-z-t-Z-xy-zt-38-xz-yt-34-xt-yz-43-x-y-z-t-




Question Number 145768 by mathdanisur last updated on 07/Jul/21
x;y;z;t∈Z^+    { ((xy + zt = 38)),((xz + yt = 34)),((xt + yz = 43)) :}  ⇒ x+y+z+t=?
$${x};{y};{z};{t}\in\mathbb{Z}^{+} \\ $$$$\begin{cases}{{xy}\:+\:{zt}\:=\:\mathrm{38}}\\{{xz}\:+\:{yt}\:=\:\mathrm{34}}\\{{xt}\:+\:{yz}\:=\:\mathrm{43}}\end{cases}\:\:\Rightarrow\:{x}+{y}+{z}+{t}=? \\ $$

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