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xy-dy-dx-y-2-x-3-x-2-1-




Question Number 89970 by jagoll last updated on 20/Apr/20
xy (dy/dx) = y^2 ((x^3 /(x^2 +1)))
$$\mathrm{xy}\:\frac{\mathrm{dy}}{\mathrm{dx}}\:=\:\mathrm{y}^{\mathrm{2}} \left(\frac{\mathrm{x}^{\mathrm{3}} }{\mathrm{x}^{\mathrm{2}} +\mathrm{1}}\right)\: \\ $$
Commented by john santu last updated on 20/Apr/20

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