y-b1x1-b2x2-c-i-need-to-arrange-the-equation-for-thd-value-of-x2-

Question Number 93057 by gonzo last updated on 10/May/20

y = b 1 x 1 + b 2 x 2 + c

i n e e d t o a r r a n g e t h e e q u a t i o n f o r t h d v a l u e o f x 2

Commented by gonzo last updated on 10/May/20

i h a v e d i s c a l c u l a a n d i t h e l p s m e w o r k k t t h r o u g h

Answered by prakash jain last updated on 10/May/20

y = b_{1} x_{1} + b_{2} x_{2} + c

subtract b_{1} x_{1} + c from both sides .

y - b_{1} x_{1} - c = b_{1} x_{1} + b_{2} x_{2} + c - b_{1} x_{1} - c

y - b_{1} x_{1} - c = b_{2} x_{2}

divide by b_{2}

\frac{y - b_{1} x_{1} - c}{b_{2}} = \frac{b_{2} x_{2}}{b_{(}}

x_{2} = \frac{y - b_{1} x_{1} - c}{b_{2}}

Commented by gonzo last updated on 10/May/20

t h a n k y o u s o m u c h

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