Question Number 83149 by 09658867628 last updated on 28/Feb/20
$${y}={e}^{\mathrm{tan}{t}\:} \\ $$
Commented by Kunal12588 last updated on 28/Feb/20
$${what}\:{is}\:{the}\:{QUESTION}\:? \\ $$
Commented by Kunal12588 last updated on 28/Feb/20
あなたの質問は何ですか ？
Commented by peter frank last updated on 28/Feb/20
$${apply}\:{ln}\:{both}\:{sides} \\ $$$${lny}=\mathrm{tan}\:{x} \\ $$$$\mathrm{ln}\:{y}=\frac{\mathrm{sin}\:{x}}{\mathrm{cos}\:{x}} \\ $$$${u}=\mathrm{cos}\:{x} \\ $$$${y}^{'} ={y}.{lnu} \\ $$$${y}^{'} ={yln}\mathrm{cos}\:{x} \\ $$