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y-old-




Question Number 111183 by mohannalamati last updated on 02/Sep/20
y^(old)
$${y}^{{old}} \\ $$
Commented by bemath last updated on 02/Sep/20
what your question ?
$$\mathrm{what}\:\mathrm{your}\:\mathrm{question}\:? \\ $$
Answered by mathmax by abdo last updated on 02/Sep/20
∼ y^(young)
$$\sim\:\mathrm{y}^{\mathrm{young}} \\ $$
Answered by bobhans last updated on 03/Sep/20
⇔ y^(afdoll.(√(great)))
$$\Leftrightarrow\:\mathrm{y}^{\mathrm{afdoll}.\sqrt{\mathrm{great}}} \\ $$

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