y-sinx-x-Differentiate-

Question Number 184184 by Mastermind last updated on 03/Jan/23

y = {(sinx)}^{x}

Differentiate

Answered by SEKRET last updated on 03/Jan/23

y = {(\sin (x))}^{x}

\ln (y) = x \cdot \ln (\sin (x))

\frac{y^{'}}{y} = \ln (\sin (x)) + x \cdot \frac{\cos (x)}{\sin (x)}

y^{'} = {(\sin (x))}^{x} \cdot (\ln (\sin (x)) + x \cdot ctg (x))

Commented by Mastermind last updated on 03/Jan/23

V . good of you, everything is correct

thank you so much for answering it