y-x-2-x-1-2-min-max-help-pls-

Question Number 26364 by d.monhbayr@gmail.com last updated on 24/Dec/17

y = x^{2} {(x - 1)}^{2}

m i n = ? m a x = ?

h e l p p l s

Commented by mrW1 last updated on 24/Dec/17

t h e r e i s n o m a x, s i n c e y \to \infty w h e n x \to \pm \infty .

y = x^{2} {(x - 1)}^{2} ⩾ 0

\Rightarrow m i n = 0

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