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y-x-sinx-find-y-




Question Number 162280 by MathsFan last updated on 28/Dec/21
y=x^(sinx)   find  y′
y=xsinxfindy
Answered by Ar Brandon last updated on 28/Dec/21
y=x^(sinx)   lny=sinxlnx  (1/y)∙(dy/dx)=((sinx)/x)+cosxlnx  ⇒(dy/dx)=x^(sinx) (((sinx)/x)+cosxlnx)
y=xsinxlny=sinxlnx1ydydx=sinxx+cosxlnxdydx=xsinx(sinxx+cosxlnx)

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