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y-x-x-2-




Question Number 128382 by arash sharifi last updated on 06/Jan/21
y=x^x^2
$${y}={x}^{{x}^{\mathrm{2}} } \\ $$
Commented by hknkrc46 last updated on 06/Jan/21
• x ∈ R ⇒ y ∈ R  • x = ∓1 ⇒ y = 1  • (d/dx)(y) = x^x^2  (2xln x + x)     :)   :)
$$\bullet\:\boldsymbol{{x}}\:\in\:\mathbb{R}\:\Rightarrow\:\boldsymbol{{y}}\:\in\:\mathbb{R} \\ $$$$\bullet\:\boldsymbol{{x}}\:=\:\mp\mathrm{1}\:\Rightarrow\:\boldsymbol{{y}}\:=\:\mathrm{1} \\ $$$$\bullet\:\frac{\boldsymbol{{d}}}{\boldsymbol{{dx}}}\left(\boldsymbol{{y}}\right)\:=\:\boldsymbol{{x}}^{\boldsymbol{{x}}^{\mathrm{2}} } \left(\mathrm{2}\boldsymbol{{x}}\mathrm{ln}\:\boldsymbol{{x}}\:+\:\boldsymbol{{x}}\right) \\ $$$$\left.\:\left.\:\::\right)\:\:\::\right)\: \\ $$

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